The definite integral ∫[a, b] f(x) g'(x) dx is equal to:
f(b)g(b) - f(a)g(a)
-[f(a)g(b) - f(b)g(a)]
f(a)g(b) - f(b)g(a)
-[f(b)g(b) - f(a)g(a)]

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